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float: left; margin-bottom: 1em; margin-right: 1em; text-align: center;"&gt;&lt;a href="http://ygs2010-sorular.osym.gov.tr/"&gt;&lt;img border="0" height="156" src="http://ygs2010-sorular.osym.gov.tr/logo.jpg" width="200" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class="separator" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em; text-align: center;"&gt;&lt;a href="http://www.blogger.com/goog_18834422"&gt;&lt;br /&gt;&lt;/a&gt; &lt;/div&gt;&lt;div class="separator" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em; text-align: center;"&gt;&lt;a href="http://www.blogger.com/goog_18834422"&gt;&lt;br /&gt;&lt;/a&gt; &lt;/div&gt;&lt;a href="http://www.blogger.com/goog_18834422"&gt;&lt;br /&gt;&lt;/a&gt; &lt;br /&gt;&lt;a href="http://www.blogger.com/goog_18834422"&gt;&lt;br /&gt;&lt;/a&gt; &lt;br /&gt;&lt;a href="http://www.blogger.com/goog_18834422"&gt;&lt;br /&gt;&lt;/a&gt; &lt;br /&gt;&lt;a href="http://ygs2010-sorular.osym.gov.tr/"&gt;&lt;br /&gt;&lt;/a&gt; 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&amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &amp;nbsp; &lt;/object&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/4316938418829730394-3898185782165866264?l=pimatematik.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://pimatematik.blogspot.com/feeds/3898185782165866264/comments/default' title='Kayıt Yorumları'/><link rel='replies' type='text/html' href='http://pimatematik.blogspot.com/2010/03/matematik-olimpiyat-sorular.html#comment-form' title='0 Yorum'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4316938418829730394/posts/default/3898185782165866264'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4316938418829730394/posts/default/3898185782165866264'/><link rel='alternate' type='text/html' href='http://pimatematik.blogspot.com/2010/03/matematik-olimpiyat-sorular.html' title='Matematik Olimpiyat Soruları'/><author><name>matematikciyiz</name><uri>http://www.blogger.com/profile/03968004638931585689</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='24' src='http://3.bp.blogspot.com/_qgK5uV_A2EI/StHtQXLKT0I/AAAAAAAAAAM/Duuj5lQDBHQ/S220/kopek-baligi-resimleri-9.jpg'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4316938418829730394.post-3562444333761245570</id><published>2010-03-21T18:29:00.002+02:00</published><updated>2010-03-21T18:31:53.501+02:00</updated><title type='text'>0 dan 444 e kadar kaç 4 rakamı var.</title><content type='html'>Bu tarz soruları çözerken sayma yöntemi de kullanabilirsiniz.&lt;br /&gt;0 dan 100 ve sonrasına kadar her rakam 20 defa kullanılmıştır.Kendi ile&amp;nbsp;başlamamak&amp;nbsp;şartı ile yani soruda &amp;nbsp;ki4 rakamı;&lt;br /&gt;0-99, 100-199, 200-299, 300-399 bu gruplarda 4 rakamı 20+20+20+20 80 defa kullanılmıştır.&lt;br /&gt;İşlem ile çözmek istersek de;&lt;br /&gt;399 a kadar yazılabilecek sayıları sayısı 400 dür.&lt;br /&gt;4.10.10=400 &amp;nbsp;ilk basamağa 0,1,2,3&amp;nbsp;gelebilir&amp;nbsp;diğer iki basamağa 10 rakam&lt;br /&gt;4 rakamının kullanılmadığı sayıları hesaplamak istersek;&lt;br /&gt;4.9.9=326&lt;br /&gt;400-326=74 yapar. Saydığımızda 80 çıkmıştı bu yöntemle 76 aradaki fark şu 4 rakamının çift kullanıldığı 44,144,244,344 sayılarının&amp;nbsp;her birinden&amp;nbsp;+1 geliyor yani 76+4=80&lt;br /&gt;400 ile 439 arasındaki sayıların herbirinde 4 rakamı vardır.&lt;br /&gt;1*4*10=40 yine 404,414,424,434 için +4 gelir elimizde var 44&lt;br /&gt;440 ile 444 arasında;&lt;br /&gt;1*1*5 =5 burada ki her basamakda çift 4 var ve 5*2 =10 444 sayısında fazladan 4 var yine +1 gelir. Artık elimizde 11 var.&lt;br /&gt;bulduğumuz sayıları toplarsak;&lt;br /&gt;80+44+11=135.......&lt;br /&gt;&lt;br /&gt;Gencer TÜLÜ&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/4316938418829730394-3562444333761245570?l=pimatematik.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://pimatematik.blogspot.com/feeds/3562444333761245570/comments/default' title='Kayıt Yorumları'/><link rel='replies' type='text/html' href='http://pimatematik.blogspot.com/2010/03/0-dan-444-e-kadar-kac-4-rakam-var.html#comment-form' title='3 Yorum'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/4316938418829730394/posts/default/3562444333761245570'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/4316938418829730394/posts/default/3562444333761245570'/><link rel='alternate' type='text/html' href='http://pimatematik.blogspot.com/2010/03/0-dan-444-e-kadar-kac-4-rakam-var.html' title='0 dan 444 e kadar kaç 4 rakamı var.'/><author><name>matematikciyiz</name><uri>http://www.blogger.com/profile/03968004638931585689</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='32' height='24' src='http://3.bp.blogspot.com/_qgK5uV_A2EI/StHtQXLKT0I/AAAAAAAAAAM/Duuj5lQDBHQ/S220/kopek-baligi-resimleri-9.jpg'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-4316938418829730394.post-1045554360314016288</id><published>2010-03-17T17:58:00.001+02:00</published><updated>2010-03-17T18:01:59.337+02:00</updated><title type='text'>8-2-1 MAtematik  yazılısı</title><content type='html'>&lt;a href="http://www.tlinkpara.com/l/MTg1OTE3"&gt;http://www.zumodrive.com/share/4dN1ZjdjOG&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;a title="View 8-2-1 on Scribd" href="http://www.scribd.com/doc/28511656/8-2-1" style="margin: 12px auto 6px auto; 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